Usage: looking for a string but wanting to exclude long lines like minified JS files which you didnt write or dont need. Note: Above is not my regex, I just copy/pasted it from some random guy who was looking for a 'dd-mm-yyyy' regex. using grep for find values larger/less than Hi I have been experimenting with grep to find values for a particular column that is greater than or less than certain s. By extension, if you want to match a specific string within a line that is no longer than say 255 characters, this would be a solution. ![]() So, let’s say we try to represent a date higher than ''. This visits all commits in the range, rather than stopping at the first commit which is older than a specific date. One can also select the exact date and time other than going back to a certain number of days: cp find. Display only changes where the changelist number is equal to, or higher than, the specified changelist number. Solved Select the columns which have value greater than particular number. This is useful when using grep in shell scripts where you want to check whether a file contains a string and perform a certain action depending on the result. If a match is found, the command exits with status 0. If your time stamp format is different, you can adjust the regular expression passed to the match function to suit it.Yes, it can be done but its really tricky and the complexity depends on how specific you want the regular expression to be. The -q (or -quiet) tells grep to run in quiet mode not to display anything on the standard output. valid log records must have a time stamp before the end time. Thus you run the awk command like so, assuming that the above Awk script is in an executable file filter-log-dates.awk in the current working directory and the log file is mylog.txt. sort -rn sorts the list numerically and in reverse, so that the first number is the biggest. ![]() Each match will be printed in a different line, as per the -o flag. grep -Eo 0-9+ file prints all matches of positive decimal integer numbers in the file. I mean positive decimal integer numbers only (I do not need to consider floating, negative numbers, octal, hexadecimal. grep -Eo 0-9+ file sort -rn head -n 1 63 Explanation. However, I am not sure if it is complete: grep -P '36 0-9+ 0-9+ 0-9' test.txt. ![]() works just fine on the very limited corpus you provided. For example: ruby /tmp/parselogdates.rb 'Tue Oct 4 11:55:18 2016' /path/to/logfile. Set up an S3 Lifecycle policy to move photos older than 30 days to the. You can modify the comparison from > to > if you really mean 'later than or equal to' your given timestamp, which may be more intuitive. You supply the start and end time through the variables starttime and endtime in a format that mktime understands ( YYYY MM DD hh dd ss). I wrote this regex to match numbers greater than or equal 3600. Using Grep & Regular Expressions to Search for Text Patterns in Linux. In_range(mktime(m " " m " " m " 00 00 00"), starttime, endtime) I present this GNU AWK script: #!/usr/bin/gawk -f If you want a more generic solution, we need to do some more programming. When it finds a pattern that matches in more than one file, it prints the name of the file. All the other current answers rely on the fact that the log file entries are sorted chronologically or the fact that the date range can be matched easily with regular expressions. The grep command can search for a string in groups of files.
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